KemicalBurn
Bluelight Crew
The plane wont take off because you guys are relying on 'zero friction'.
JeffreyDahmer said:^ ...at exactly the same speed. That's rather an important omission.
I now understand where my own confusion arises. If the plane does not move forward (because of the equal speed but opposite motion of the plane and the belt) the plane cannot possibly take off.
If the plane is able to move forward at a fast enough speed to allow the wing to create lift, it can surely take off.
In all my visions of the problem so far, the plane has not moved forward. Now i see this problem as analogous to the runner on the treadmill. If the runner runs faster (the plane speeds up) the treadmill runs faster in the opposite direction to keep the runner in the same position (say, relative to somebody standing next to the treadmill).
Replace the runner with the plane and there is no movement forward. No movement forward means no airflow over the wing. The plane can not take off.
KemicalBurn said:The plane wont take off because you guys are relying on 'zero friction'.
MazDan said:If the plane has wheels then the answer is NO. (Actually to be more precise the question cannot have an answer.......its a bit like the chicken and the egg)
Reason. There IS a relationship between the wheels of the plane and the conveyor belt. Anytime the plane moves forward (lets say one rotation of the wheels) the conveyor belt must move backwards by an identical ammount.
bGIveNs33 said:There is movement forward. Your runner on a treadmill argument isn't good. Look at my rollerblader on a treadmill argument, which i have stated probably 7 times. That is what is really happening.
KemicalBurn said:This simply isnt the case. Your rollerblade/treadmill analogy is weak - here's why:
*the conveyor belt moves in the opposite direction of the plane and at exact the same speed.
*your analogy doesnt take into account that if the pilot were to get out and push (which is the basis of your analogy) you arent taking into account that the conveyor belt will counter-act this by speeding up. which has already been stated that it will.
bGIveNs33 said:A pilot getting out and pushing is ridicolous, because he would be on the treadmill, dealing with that same friction. That is NOT the same thing. If he were to tie to ropes to it(on either side) and pull it forward from a source of the conveyor belt, now that is the same thing. Again, this is basic physics, the force from the propeller is greater that the force of the friction. That is all that is going on. Very Very basic.
Yeah.I'm bad about that.I got add i think.bGIveNs33 said:nice sig sickpuppy........ but it's obivious you read the question and skipped the rest of the thread![]()
johnnyb420 said:i think alot of you are confusing physics with aerodynamics with out lift the plane can apply all the power it wants it will not fly .
by your arguement would the plane would fly if it was tethered to a pole?
-T{H}R- said:It certainly will fly because it is moving. The fact that it is moving will allow it to create lift.
But aren't you assuming a conveyor belt which can respond instantly and perfectly to the plane? Both cases are idealised. If you accept the existance of such a perfect conveyor belt (which itself must have zero mass or experience infinite force, or else it's reactions cannot be instant) then you accept no friction.KemicalBurn said:AN didnt account friction.
You're running on a treadmill, and no matter how fast you run, the treadmill keeps you in the same place. Your friend walks round to the front of the treadmill, sticks his arm out, you grab it and he yanks you off the the treadmill against the flow of the treadmill. By having an additional force which isn't having to act against the treadmill, you can easily overcome it. Same goes for the "yank" the engines give the plane.johnnyb420 said:it says that movement in one direction is conteracted in the other direction in my calclation that means it does not move,of if it reaches liftoff speed in the forward direction it will takeoff the qestion is not if it can overcome this imaginary conveyer the way the question is parced it does not move