hussness
Bluelighter
This is probably more of a thurough answer than Beenhead wants, but I'm just trying to procrastinate from doing Differential Equations.
Mescaline is 2-(3,4,5-trimethoxyphenyl)ethaneamine. This means that it has a primary amine. This amine in many cases acts as a Bronsted/Lowry base and accepts a proton to become the 2-(3,4,5-trimethoxyphenyl)ethanaminium cation. In the case of using HCl as the acid, chloride is the conjugate base and the anion that stabilizes the aminium cation present on the protonated Mescaline. This separation of charges between the aminium cation and chloride anion causes Mescaline HCl to behave more like an ionic compound. Ionic compounds tend to dissolve better in water, which as a large dipole moment. A lot of them also form better crystals, and have significantly different melting points and boiling points, as nuke alluded to. In general, the relationship governing the behavior of a molecule with a certain pKa in a solution with a certain pH is governed by the Henderson-Hasselbach equation:
pH = pKa + log([A-]/[HA])
Mescaline is 2-(3,4,5-trimethoxyphenyl)ethaneamine. This means that it has a primary amine. This amine in many cases acts as a Bronsted/Lowry base and accepts a proton to become the 2-(3,4,5-trimethoxyphenyl)ethanaminium cation. In the case of using HCl as the acid, chloride is the conjugate base and the anion that stabilizes the aminium cation present on the protonated Mescaline. This separation of charges between the aminium cation and chloride anion causes Mescaline HCl to behave more like an ionic compound. Ionic compounds tend to dissolve better in water, which as a large dipole moment. A lot of them also form better crystals, and have significantly different melting points and boiling points, as nuke alluded to. In general, the relationship governing the behavior of a molecule with a certain pKa in a solution with a certain pH is governed by the Henderson-Hasselbach equation:
pH = pKa + log([A-]/[HA])

