fastandbulbous
Bluelight Crew
Cagliostro said:You need to think more thoroughly, FnB. Let's assume:
Compound X: 5-HT2A 30% activation; 5-HT2C 25% activation at 10 nM.
Compound Y: 5-HT1A 65% activation; 5-HT2A 30% activation at 10 nM.
Then our mixture will give us: 5-HT1A 65%; 5-HT2A ~60%; 5-HT2C 25%. That's the sum.
That one inhibits the metabolism of the other is speculation unless you have proof that is does.
Not really as they'll be acting in a way analogous to competetive inhibitors ie they will be competing with each other for receptor occupancy. The figures you give are purely for when the drug is interacting on it's own with the specific receptor (and competetive activity is determined from Michalis-Menton enzyme kinetics type calculation, which arent linear - it's the reciprocals that show a linear relationship)