There is a 5HT2s receptor saturation point for LSD, I've heard 500 mics in some place and 1500 mics in others.. I wish I knew the exact data this was based off of. In either case, it is not a phenomenally high amount relative to the potency.
Receptor regulation. Maybe two people have
N number of receptors but one person has less
E serotonin per receptor at any given point in time. So his initial regulation
Ri(N, E) = k(E/N) would be higher. Therefore, when both people take take
m mcg's of acid, the guy who had a higher regulation (lower serotonin per receptor) would feel it more. Come to think of it, this doesn't affect the saturation point at all. But anyway, say we make
S (for sensitivity of highness) =
S = k(E/N) = Ri
* It is important to understand that H/N (serotonin per receptor) may intuitively sound proportional to how high you
feel, however you must keep in mind that these values are the day-day sober constants, so we can make the distinction that there is no correlation between how high one feels and his sensitivity
before drugs are involved.
How is the dosage related to all this? How do we take into consideration saturation point? This brings us to the next point: how many receptors you have. Research shows that individuals with ADHD have a lower amount of dopamine receptors. It is a safe presumption to say the same thing can be applied to serotonin. In other words, a person with half the receptors of another will reach his or her saturation point
A at half the dose. Therefore:
A ∝ N
When A, N, and Ri are known and held constant, what affect does dosage have on the highness? Our team of scientists found out that the dosage increases relative (thought not linear) to the increase in serotonin, which makes sense. In mathematical terms, it appears
highness H is equal to the
new serotonin/receptor ratio Sr divided by the sober sensitivity
S0 - 1 (the -1 is there so that if Ef = Ei, there is no change, thus no highness)
Ef (final serotonin) = L (amount contributed by LSD) + Ei (initial serotonin)
H = (Sr / S0) - 1 = (Ef/N) / (Ei/N) - 1 = Ef/Ei -1 = (L + Ei)/Ei - 1 = L/Ei
If the amount of highness one feels is equal to L/Ei (amount of serotonin contributed from LSD / initial serotonin), what exactly is
L in relation to
m (mcg of LSD)? As discussed above, the saturation point is proportional to
N number of receptors. But what kind of effect does the proportion have on the saturation point?
To find out, our scientists gave 50 kids LSD. It was noted that each of them responded to dose curve relative to their dose, and a horizontal asymptote at their "maximum highness" and an intercept at (0,0). In other words. As the dose approaches infinity, their highness approaches a certain number. Furthermore, all other variables constant, their highness varied precisely according an arctan function. So the steps of deriving the highness function are as follows:
H = arctan(S*m)*2pi*A/Ei = (since A∝N) = arctan(S*m)*2pi*kA/Ei = arctan(kS*m)*2pi*kRi^-1 =
Thus we have related the highness to
N number of receptors
Ei average serotonin per receptor in a sober state
m Amount of LSD in mcg
H(N, Ei, m) = P*arctan(Ei/N * km)*2pi*(N/Ei)
Where P is the yet to be determined Peter constant, and k is the microgram conversation constant.
If anyone could find out the value and units for k and P that would be awesome.