dread
Bluelighter
But I was wrong, too: Even when the pyrrolidine aromatizes to pyrrol, the ring won't be charged. So, the concerns about a MPTP-like derivative were not justified. Silly me
*slaps forehead*
Of course! It's so simple. In a pyrrole ring, just like in an indole ring, the nitrogen has one bond free for the methyl, so it won't become charged, unlike a pyridine ring, where the nitrogen already has a double bond and a single bond.
Now we are all gonna feel real silly.


