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Ratio of ascorbic acid to crack: is this calculation right?

xxl

xxl

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Taking C to have a molecular weight of 300 and ascorbic acid to have a molecular weight of 176, this would mean to reacidify 4 g of crack one would need 4 g x 0.58 = 2.3 g ascorbic acid. Is it that simple?
 
Ascorbic acid molar mass = 198
Cocaine = 303

So you will need 2 grams of ascorbic acid for 3 grams of crack, assuming the crack is pure, which it probably is not.
 
Using ascorbic acid you get the ascorbate, which is not snortable (probably forms a hygroscopic glue). It's injectable however. This is useful if you want to purify your blow on the cheap. Acid ---> base ---> Acid. Water soluble cuts remain in the water.

Regarding dread's remark that "So you will need 2 grams of ascorbic acid for 3 grams of crack, assuming the crack is pure, which it probably is not", I surmise that if the crack is not pure it will contain residual bicarbonate (or the ammonium if ammonia was used), and since bicarbonate needs to be neutralized too, and indeed has a lower molar mass than ascorbic acid, one might need more ascorbic acid than if the crack were pure, not less. But I get the picture. Thanks for the pointers guys. I was a bit worried about where the H+ come from in the ascorbic acid molecule and whether 1 ascorbic acid molecule wouldn't be able to neutralize 2 C molecules instead of one.

P.S. Overacidifying dammages veins, that's why getting the proportions right is more than academic. By the way, I suppose the citrate and the acetate are not snortable either, otherwise they would be well-known.
 
Last edited:
I think dread is also referring to adulterants that survive basification.

...and whether 1 ascorbic acid molecule wouldn't be able to neutralize 2 C molecules instead of one.
Click to expand...

Ascorbate's second ionization has a pKa of 11.6.
 
xxl said:
Using ascorbic acid you get the ascorbate, which is not snortable (probably forms a hygroscopic glue). It's injectable however. This is useful if you want to purify your blow on the cheap. Acid ---> base ---> Acid. Water soluble cuts remain in the water.
Click to expand...


Thanks for the clarification :)

I don't know what I was thinking... you'd need citric acid to get citrate...
 
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