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  • EADD Moderators: Shambles

kate clean your box out :)

The mechanical work can be defined as

\Delta E_k = F \cdot s

where E_k is the kinetic energy, F is the force (the thrust of the rocket which is considered constant), and s is the distance. Differentiating with respect to time, we obtain

\frac{\operatorname{d}E_k}{\operatorname{d}t} = F \cdot \frac{\operatorname{d}s}{\operatorname{d}t}

or

\frac{\operatorname{d}E_k}{\operatorname{d}t} = F \cdot v

where v is the velocity. Dividing by the instantaneous mass m to express this in terms of specific energy (e_k), we get

\frac{\operatorname{d}e_k}{\operatorname{d}t} = \frac F m \cdot v = a \cdot v

where a is the acceleration vector.


No not really.
 
Chill guys I've got knitting to be doing for kittens like eh....

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