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  • EADD Moderators: Pissed_and_messed | Shinji Ikari

EADD Puzzle Corner

Nonsense. It's 20 days. I'm way too tired to read through all that and assimilate it; so can you (or someone else) just tell me plainly where you got the extra day from??

Make sure you're not using zero-based numbering, start counting from day 1 not day 0.
 
No, it still makes 20.

Julies answer doesn't make sense. It starts off with four days of smoking, and then a fifth day of collecting the 0.2 collected gear in the tooter. Then, in the next cycles it changes to 3 days of smoking, and then a fourth day of smoking a collected 0.2g of gear. By doing this, it's returning 1gram of collected smoke in the tooter, which does not comply with the rule that "1 quarter of 3.2 grams of gets collected in the tooter.













OK here's a new one.



Julie has been smoking gear for X years

Julie has killed Y amount of brain cells in that time.

Julie is M


What is the value of X and Y, if M = Beyond comprehending mathematics anymore
 
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None of you got it right!

Actually, who says he doesn't make a second tooter in each day to get what was caught in the first? He doesn't deserve to be called a junkie!

In which, case, he does smoke 0.2g a day... which means it is 16 days & 2.4m assuming the 2nd question was in relation to the first. (15x30 each day= 1xPlate, 1xWrap, 2xTooters) :p
 
No, it still makes 20.

Julies answer doesn't make sense. It starts off with four days of smoking, and then a fifth day of collecting the 0.2 collected gear in the tooter. Then, in the next cycles it changes to 3 days of smoking, and then a fourth day of smoking a collected 0.2g of gear. By doing this, it's returning 1gram of collected smoke in the tooter, which does not comply with the rule that "1 quarter of 3.2 grams of gets collected in the tooter.
Yes. Because after day 4, there is 0.2 g in tooter #1; which gets smoked on day 5, and leaves behind 0.05 g in tooter #2 at the beginning of day 6. It only takes three more days to get another 0.15 g. of build-up in there. Hence the switch from a 5-day cycle to a 4-day cycle: it only takes 3 days to fill up a tooter that already has a quarter of a day's worth in it.

Even if Jake was to begin by smoking the whole 3.2 g., 0.2 g. at a time, that would last 16 days and leave behind 0.8 g. 0.8 g. is enough for another 4 days (making 20 days), during which time 0.2 g. of it gets deposited back in the tooter -- and that is enough for another day, making 21 days in total.
 
Actually, who says he doesn't make a second tooter in each day to get what was caught in the first? He doesn't deserve to be called a junkie!

Exactly - you always make another tooter to toot the gear from the tooter of the tooter, or summat...

Plus, why bother making a new wrap everyday? That's just wasteful of foil! In any case, a proper junky wouldn't need to make any new wraps 'cos they'd have smashed through it in a couple of days tops =D
 
To relate the surface integral of the curl of a vector field F over the foil's surface Σ in Euclidean three-space to the line integral of the tooter's inner vector field over its entire boundary ∂Σ:

5f65e93751487f9350c194aa5f2bb8de.png

thats almost made my day, euclid, calculous and tooters in the same sentence. love it
 
None of you got it right! The answer is 21 days and 172.5 cm. of foil. Here's the explanation:
NSFW:
Day 1, Jake smokes 0.2g. He needs a plate to smoke it from, a tooter and a wrap to restash it afterwards. P=1 T=1 W=1.
Day 2, Jake smokes another 0.2g through yesterday's tooter. He still needs another plate and another wrap. P=2 T=1 W=2.
Day 3, Jake smokes yet another 0.2g. P=3 T=1 W=3
Day 4, Jake smokes yet another 0.2g. P=4 T=1 W=4
Day 5, Jake unrolls the tooter (which now has collected 0.2g.) He only needs to make a new tooter (which will collect 0.05g) to smoke this (no plate, and nothing to restash). P=4 T=2 W=4.
Day 6, Jake smokes 0.2g. from his stash through yesterday's tooter, needing a fresh plate and another wrap. P=5 T=2 W=5.
Day 7, P=6 T=2 W=6.
Day 8, P=7 T=2 W=7.
Day 9, and again there is 0.2g in Jake's tooter. P=7 T=3 W=7.
Day 10, P=8 T=3 W=8.
Day 11, P=9 T=3 W=9.
Day 12, P=10 T=3 W=10.
Day 13, full tooter again, P=10 T=4 W=10.
Day 14, P=11 T=4 W=11.
Day 15, P=12 T=4 W=12.
Day 16, P=13 T=4 W=13.
Day 17, another full tooter. P=13 T=5 W=13.
Day 18, P=14 T=5 W=14.
Day 19, P=15 T=5 W=15.
Day 20, Jake's original stash runs out, so he does not need to make another wrap. P=16 T=5 W=15.
Day 21, and there is still 0.2g. in Jake's (fifth) tooter.

By the end of day 21, Jake has got through sixteen plates, six tooters and fifteen wraps. This can be made from 157.5 cm. of foil, with careful tearing. (120 cm. for 16 plates, 22.5 cm. for 6 tooters and 30 cm. for 16 wraps including one which does not get used.)

There was nothing about only being able to collect 0.2g in each tooter in the original rules.
 
There was nothing about only being able to collect 0.2g in each tooter in the original rules.
Only that that's a sensible amount to allow to collect, since it never has to be subdivided.

If you used one tooter to smoke the whole 3.2 g., then you'd have to make at least a second to smoke the 0.8 g. you caught, and a third to smoke the final 0.2 g. So you would save 7.5 cm. of foil, at the expense of a more complex smoking procedure. You'd also have a tooter and a wrap left over. Come to think of it, if you were to dispense with making a wrap on the last-but-one day of the original stash, by simply melting the final 0.2 g. straight onto a plate instead of wrapping it, then you could even save a further 7.5 cm. of foil, since the leftovers now amount to two wraps and a tooter .....
 
Only that that's a sensible amount to allow to collect, since it never has to be subdivided.

If you used one tooter to smoke the whole 3.2 g., then you'd have to make at least a second to smoke the 0.8 g. you caught, and a third to smoke the final 0.2 g. So you would save 7.5 cm. of foil, at the expense of a more complex smoking procedure. You'd also have a tooter and a wrap left over. Come to think of it, if you were to dispense with making a wrap on the last-but-one day of the original stash, by simply melting the final 0.2 g. straight onto a plate instead of wrapping it, then you could even save a further 7.5 cm. of foil, since the leftovers now amount to two wraps and a tooter .....

That makes sense. Well done, that was a devious little puzzle.

I wish you'd not be so quick to give the answer, and see if anyone managed to guess it.
 
It all sounds fair ..... it's a perfectly even chance ..... However, you notice from the way his pencil moved that he has actually written "LEAVE" on both pieces of paper.

How can you keep your job?

As its pencil just rub it out and write 'stay' on it ?
 
Odd Girl Out

Getting colder now. And you were so warm before .....

O.K., try this then. This one's easy. Which is the odd one out:

Beckie, Mandy, Nikki, Toni.

NSFW:
[spoil]PYHR: Vzntvar lbh ner gurve zbgure, gryyvat gurz bss nsgre fbzr rkgerzr anhtugvarff.[/spoil]

NSFW:
[spoil]PYHR: Vg fubhyq or boivbhf, vavgvnyyl. Gung'f gur ybat naq fubeg bs vg.[/spoil]
 
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That's always the trouble with "odd one out" puzzles -- that it could be any of them for different reasons; but there's a specific, strong -- and blindingly obvious, when you know it -- reason I had in mind when I set it, why one of those is not like the others.

If you have to use the clues, don't spoil it for everyone else .....
 
Possible answer?

NSFW:
Well, my initial instinct is Beckie, Nikki & Toni all have an 'i' in their name whilst Mandy doesn't

More fun was probably figuring out what language/cypher that was... ROT13 it appears.
 
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