haribo1
Ex-Bluelighter
- Joined
- Nov 29, 2006
- Messages
- 4,822
the trans-5,9-diCH3 (beta) isomer is where most of the potency lies.
Metazocine X=CH3 , Y=OH = 1/5 x morphine
Pentazocine X=allyl , Y=OH = 1/5 x morphine
Phenazocine X=phenylethyl. Y=OH = 4 x morphine
Thiazocine X=2 thienylethyl Y=OH = 8 x morphine
Cyclazocine X=methyl cyclopropyl Y=OH = 10 x morphin
8-CAC X=methyl cyclopro Y=CONH2 = 12 x morphine
Last edited:
