2C-B HCl Solubility

[zaggy]

Hypothetically, if one were to have 2C-B HCl, how would they make a 5mg/mL solution in water with 500mg of substance?

Thanks in advance.

 

[sekio]

Dissolve it in 100ml of water? Is this a trick question of some sort?

 

[zaggy]

Dissolve it in 100ml of water? Is this a trick question of some sort?

Nope, just simply not familiar with the solubility of 2C-B, specifically the HCl salt. Noob-ish.

 

[3rd_I_blind]

The HCl salt is not really soluble in water and it usually takes some time and a lot of stirring to disolve. You could try adding a few drops of vinegar to acidifiy the solution, or add some ethanol to increase solubility.

 

[zaggy]

The HCl salt is not really soluble in water and it usually takes some time and a lot of stirring to disolve. You could try adding a few drops of vinegar to acidifiy the solution, or add some ethanol to increase solubility.

Thanks, this is the info I was looking for. My main question is what the mg/mL solubility would be in such a solution, and what proportions of dH2O and 2C-B I would use to make a 5mg/mL solution.

Could something like this be stored for a long time in the fridge?

 

[adrian89987]

I would maybe dissolve 500mg in 100mL of vodka or something similar. Generally compounds in solution are less stable than the solid however the phenethylamines are fairly stable AFAIK. Having the compound in a sufficiently alcoholic solution would first off help ensure proper solubility but also ward off growth within your solution which is important when trying to store the solution for long periods.

I have no idea what the solubility of 2c-b HCl is in water though.

 

[3rd_I_blind]

2C-B is very stable in solution, so you shouldn't worry about that.

As for the solubility in mg/mL, there's no reliable information on that. I suggest you just start with 10 mg and see if you can dissolve that into 2 mL. If not, add 1 drop of vinegar and see if that changes anything. If that does not change anything, try again with something like wodka or just a 50/50 mixture of water with ethanol. Again, try to dissolve 10 mg in 2 mL, I would be very surprised if this would not work with 40-50% ethanol in H2O.

As for the proportions, the fraction of 2C-B can be disregarded with respect to the H2O. So just add 100 mL of your solution and 500 mg of 2C-B together, the resulting volume will be close enough to 100 mL to just assume it is 100 mL. Of course you could make it a perfect 100 mL by just dissolving in 90 mL first and then filling it up to 100 mL once all your 2C-B is in solution.

 

[zaggy]

2C-B is very stable in solution, so you shouldn't worry about that.

As for the solubility in mg/mL, there's no reliable information on that. I suggest you just start with 10 mg and see if you can dissolve that into 2 mL. If not, add 1 drop of vinegar and see if that changes anything. If that does not change anything, try again with something like wodka or just a 50/50 mixture of water with ethanol. Again, try to dissolve 10 mg in 2 mL, I would be very surprised if this would not work with 40-50% ethanol in H2O.

As for the proportions, the fraction of 2C-B can be disregarded with respect to the H2O. So just add 100 mL of your solution and 500 mg of 2C-B together, the resulting volume will be close enough to 100 mL to just assume it is 100 mL. Of course you could make it a perfect 100 mL by just dissolving in 90 mL first and then filling it up to 100 mL once all your 2C-B is in solution.

Thanks, this is exactly what I needed to know. Lol do they make mL measuring cups? Because a graduated cylinder is the only thing I can think of, and there ain't much space to stir in there.

 

[adrian89987]

You could use a graduated cylinder and then place in a different container for mixing. I believe there are measuring cups that have mL on them. Alternatively could use a large syringe if you can find it. Or convert from ounces or other units such as table spoon though that won't be very accurate. Also could do by mass. If you add ethanol then I believe you can use the following equation to determine the new density:

(0.789) (x) + (1.000) (1 - x) = density; where x is the fraction of alcohol present.

 

[3rd_I_blind]

The density of an alcohol/water mixture is not linearly related to the ratio of ethanol and water, since the total volume of the mixture decreases in comparison with the volumes of water and ethanol added (...this probably sounds a lot more complicated than it should, LOL). So I wouldn't suggest doing it by weighing.

I suggest you just try to dissolve 10 mg in the manner described below. Then come back for further questions if that does not work out. I think it's only getting more complicated than necessary by seeing all kinds of 'problems' before you've actually encountered them. This is not meant offensive, but in my experience it's just better to just go ahead and try something, big chance it'll dissolve just perfectly and there is not any need for stirring.

Good luck!

 

[zaggy]

The density of an alcohol/water mixture is not linearly related to the ratio of ethanol and water, since the total volume of the mixture decreases in comparison with the volumes of water and ethanol added (...this probably sounds a lot more complicated than it should, LOL). So I wouldn't suggest doing it by weighing.

I suggest you just try to dissolve 10 mg in the manner described below. Then come back for further questions if that does not work out. I think it's only getting more complicated than necessary by seeing all kinds of 'problems' before you've actually encountered them. This is not meant offensive, but in my experience it's just better to just go ahead and try something, big chance it'll dissolve just perfectly and there is not any need for stirring.

Good luck!

It's all good, you've been of great help. All of you guys have helped alot.
This is something that will happen in due time, as I'm merely window shopping this 2C-B HCl (drools), and I'm the type that researches everything a long time before even receiving it. Can't wait to actually buy some, I've never done this compound before. It seems fantastic.

 

[3rd_I_blind]

It's definitely fantastic, although for myself I'm more fond of the intermediate duration 2C-compounds (2C-I/E/T-2), and the substituted tryptamines (5-MeO-MiPT and 4-AcO-DiPT ftw).

Good luck and have fun with it, once you have it!

 

[zaggy]

Will do! I have some 2C-E sitting around of unknown quality, supposedly at a heavy mg dose (24-28mg). Still waiting for time to do that.

I have no access to any exotic trytamines or phenethylamines, as I don't know that many people or vendors :/