^The last one surely WOULD be the most active. But how to make it without ending up with 2 isomers. I assume you dehydrate the trophine and add across the double-bond, but your going to get 4 isomers I assume (correct me if I'm wrong).
Of course, if you go through the dehydrated molecule, then you could add a methyl group where the COOCH3 is since I heartell it's very active...