Rectify
Bluelighter
- Joined
- Oct 20, 2008
- Messages
- 12,136
Want To Mathematically Derive The Equation For Every Dimension? It Can Be Done Using Only The Physically Measurable Formulae For A 2D Circle Equals Pi Radius Squared And A 3D Sphere’s Volume Equals Four Thirds Pi Radius Cubed. Use Fractions; They Are More Accurate. Also, A Working Understanding Of Calculus Helps Figure This Mystery Out. Orthogonality Permits Dimensional Traveling.
Zero D, a point = (O/O)(pi^O)(radius^0)
One Dimension, a line = 2 r
2D, a circle = pi r squared
3D, a ball = 4 / 3 pi radius cubed
There Are An Infinite Number Of Dimensions. They Max Out At 6D, Then 5D, And 7D Numerically.
What Is Pi?
The Circumference Of A Circle Divided By The Circle’s Diameter. Draw A Circle, Then Use A Ruler.
I Am Not Exactly Sure Why, But Starting At 4D And Also For 5D, The Pi Is Squared. For 6D And 7th D, Pi Is Taken To The Fourth Power And Ad Infinitum To Infinity. So, 8D And 9D Have Pi Being Taken To The 6th Power und so weiter.
As D —> Infinity, The Size Of These Dimensions Approaches Zero Asymptotically.
Zero D, a point = (O/O)(pi^O)(radius^0)
One Dimension, a line = 2 r
2D, a circle = pi r squared
3D, a ball = 4 / 3 pi radius cubed
There Are An Infinite Number Of Dimensions. They Max Out At 6D, Then 5D, And 7D Numerically.
What Is Pi?
The Circumference Of A Circle Divided By The Circle’s Diameter. Draw A Circle, Then Use A Ruler.
I Am Not Exactly Sure Why, But Starting At 4D And Also For 5D, The Pi Is Squared. For 6D And 7th D, Pi Is Taken To The Fourth Power And Ad Infinitum To Infinity. So, 8D And 9D Have Pi Being Taken To The 6th Power und so weiter.
As D —> Infinity, The Size Of These Dimensions Approaches Zero Asymptotically.
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