(RC's)Accurate dosing via 'Evaporating Solution' method. Help?

[Psyke]

I want to be able to dose something like 2c-e in 1-mg increments, so I can know what works for me and to convey accurate doses whenever I report on my experience.
I can't stand when someone says 'Yeah 4-AcO-DMT worked great for me, I ate ~15 but no more than 25mg my first time."


One idea I had was to dissolve a given substance in a very small amt. of a suitable solvent and mix the liquid with a premeasured, larger quantity of an inert food powder (maltodextrin, powdered sugar, whatever) so that it was evenly "absorbed" by the powder, and the solvent was allowed to dry off. Then, the total mass could be recorded, and assuming pure active ingredient, then each 1mg of active ingredient would be contained in, say, 20mg of impregnated powder.

Has anyone heard of this being done? Would you be able to think of some reasons why this wouldn't work or how it might affect stability of the substance? BTW if it wasn't already clear, I'm not doing this to 'cut' a substance. That's some fucked game, esp. with the RC's. I really am looking for a way to make this work. As always,
thanks in advance for your help;
any anecdotal reports are of course appreciated.

 

[Psyke]

A few add-ons:

-Of course i have a mg scale, but i want to know down to the dot how much i am taking for future accurate research.

-When the solution is evaporated, will the resulting sugar/2c-e powder be consistent?
Or would the 2c-e with a different mass or etc not be consolidated into the sugar,
allowing the 2c-e to sink to the bottom? (i.e not equally ubiquitous?)

 

[tBirdee]

Wouldn't it be pretty hard to perfectly distribute the compound into the filler though?

 

[TheAzo]

No, you can't rely on that. When you have a solid powder or matrix, wet with a solvent, containing some chemical of interest, as you evaporate the solvent, the chemical of interest can migrate towards the surface.

Happens due to capillary action. The gap between grains of powder act as capillaries, and the solvent evaporates at the surface, and more solvent is drawn up through capillary action, carrying with it the chemical of interest.

The extent to which this happens varies depending on the solvent, the inactive solid, and the chemical in question, the amount of solvent used (less is better), as well as the conditions under which the solvent is evaporated. But the point is, you cannot assume this will give an even distribution.

 

[Psyke]

Thanks,
That's pretty much what i was thinking,
but i needed some confirmation.