N&PD Moderators: Skorpio | someguyontheinternet
Question about planar rings and such; couldn't cyclohexadiene work as an isostere? It's a lot flatter than cyclohexane:
Amphetamine: https://i.imgur.com/wiFudTm.png
1,4-Cyclohexadiene analog: https://i.imgur.com/ipiNJDU.png
Cyclohexane analog: https://i.imgur.com/4TlqmpW.png
You have the hydrogens on the saturated carbons sticking out of plane but the rest is flat.
Yeah it's an intermediate.. but I can check Shulgin's last big book to see if I see any PEA's with an extra methylene spacer.. (let alone an aldoxime, which just seems reactive))?
Question about planar rings and such; couldn't cyclohexadiene work as an isostere? It's a lot flatter than cyclohexane:
Amphetamine: https://i.imgur.com/wiFudTm.png
1,4-Cyclohexadiene analog: https://i.imgur.com/ipiNJDU.png
Cyclohexane analog: https://i.imgur.com/4TlqmpW.png
You have the hydrogens on the saturated carbons sticking out of plane but the rest is flat. It's not aromatic of course but I'm curious as to how it would work out.
If you want to replace the cyclohexyl in ketamine with a phenyl ring, then it can't have the keto moiety.
Thanks for the input @solipsis
It seems that I am on a kick with -FLY derivatives. They interest me a lot. I was wondering if any of the following -FLY derivative would be in theory psychoactive at all.
Thanks!
Question about planar rings and such; couldn't cyclohexadiene work as an isostere? It's a lot flatter than cyclohexane:
Amphetamine:
![]()
1,4-Cyclohexadiene analog:
![]()
Cyclohexane analog:
![]()
You have the hydrogens on the saturated carbons sticking out of plane but the rest is flat. It's not aromatic of course but I'm curious as to how it would work out.
cyclohexadiene is unstable under normal conditions: easily oxidized by air to give the corresponding benzene (driving force = aromaticity energy gain). This is the reason why products of such compounds always contain [Oxidation] inhibitor such as BHT. But if one of the two sp3 carbons of the cyclohexadiene is di-substituted (say by 2 methyls), then it should be fine. But disubstitution of one of these carbons will make you loose even more in terms of planarity of the system).
You can't have both the amine and the aryl group either, you end up with biphenyl or a substituted aniline.
at least this one won't be possible in my opinion. sp2 hybrid orbitals are oriented in a planar fashion. so you cannot have these bonds from the C=C sticking downwards the way they do. energetically extremely unfavorable.
at least this one won't be possible in my opinion. sp2 hybrid orbitals are oriented in a planar fashion. so you cannot have these bonds from the C=C sticking downwards the way they do. energetically extremely unfavorable.
also this diazo group forming the 3-ring will be extremely reactive and might disintegrate very fast to release nitrogen gas (possibly leaving behind a carbene which is very reactive and might turn the olefine into an alkine).