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Ever used Marquis reagent to test LSD blotter?

Quantum Perception

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Jan 22, 2009
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Is it best to use the whole blotter, half, or a corner?

Anyone have experience with this?

Also, LSD with Marquis comes up olive black. But would the dye on the blotter affect the outcome?

Thanks.
 
They make lsd specific reagent now... its called ehrlich and available from EZ-test...

I've yet to test an lsd blotter with marquis so I can't say for certain... but dyes in ecstasy pills don't typically effect test results for marquis so I would assume dye in blotter paper wouldn't either...
 
Marquis Reagent & LSD

I believe that marquis reagent showing LSD as olive-black is a myth. I have seen good liquid tested with both modified ehrlich's reagent and marquis and samples that tested positive (purple) with ehrlich showed orange with marquis. I have also seen good blotter tested with Marquis, and I understand why they would say olive-black. My assumption is that the olive-black is either a result of the blotter charring or the way the orange is misinterpreted when tested in the paper.

Ehrlich reagent is much simpler though. The purple is unmistakable.

Boy, I wish I could post pics. :\
 
Marquis is sulphuric acid, anything that is prone to oxidation to the extent of charring albeit sugary compounds in pills or whatever could be expected to color black if I'm not mistaken. But it does depend on quantities and the stability of the molecule.

Here's the purple from an LSD test. Ehrlich is for Indoles I think, perhaps "modified Ehrlich reagent" is what is used for LSD specifically:

ptest-lsd
 
^ I hadn't yet got my caffiene fix before thinking about answering... the paper will in fact fuck up the marquis.... the dye won't but the paper most certainly will... I've wiped up marquis with paper towels and it burns them brown/black almost instantly...

Thank you @solipsis for noticing my error... your definately correct, the sulfuric acid reacts quite a lot with paper.... perhaps this is where people are getting olive colored results?
 
So just out of curiosity how is one to test blotter for the presence of LSD? Is there a way to extract the adulterants or??
 
I got the color chart from the department of justice, so it's the feds that say this stuff turns olive black.
But damn so the blotter paper will affect the results of the test? I only ask because i remember seeing someone in another thread positively identify a DO-X blotter using marquis and he tested two blotters and both came up different colors. So idk I'm waiting to see if anymore info can come out of this.
 
So just out of curiosity how is one to test blotter for the presence of LSD? Is there a way to extract the adulterants or??

Sure there is, using some alcohol or distilled water you can extract LSD or other compounds from the paper, usually extracting 3 times should get you a nice high yield (just consider DMT extraction and other types...) if you're interested in quantity... but do not use an excess of solvent (liquid).
If you use a reagent with that I'm not sure if the dilution would make you not see the color without a spectrometer, so that might be the biggest problem. Letting some solvent evaporate might help but be careful with degradation of course (again IF you are interested in quantity).

Actually I just realized how LSD is probably quantitatively measured in the lab: exactly like that: with a spectrometer. There is probably a reagent used with a known amount of light emission at a particular wavelength per mole / number of molecules. If you extract a blotter with a fixed volume and add a fixed amount of reagent you could then subtract the measured spectrometric value from the baseline value from the reagent alone. The amount of LSD that has reacted then corresponds with the amount of light emitted at a shifted wavelength.

If there is no suitable reagent known to cause a shift in light emission or absorption I guess it's feasable to detect the UV absorption by LSD itself. I've worked with UV absorption arrays in the past.
 
Actually I just realized how LSD is probably quantitatively measured in the lab: exactly like that: with a spectrometer. There is probably a reagent used with a known amount of light emission at a particular wavelength per mole / number of molecules. If you extract a blotter with a fixed volume and add a fixed amount of reagent you could then subtract the measured spectrometric value from the baseline value from the reagent alone. The amount of LSD that has reacted then corresponds with the amount of light emitted at a shifted wavelength.

It would be much easier to use HPLC or some other type of chromatography for quantitative determination, IMO. There's a serious limit to the quantitative sensitivity that you can get below a certain point in the UV region, it really depends on the wavelength that LSD absorbs at. I would just as soon skip the spectroscopy entirely and make a series of standards and run the lot on the HPLC or a similar instrument. This method also seems preferable because it will separate any contaminants from the solution, whereas spectroscopic methods could be inaccurate due to the presence of trace amounts of other UV-absorbing species in the sample.
 
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