2CB (HCL) hidrolchlorid / hidrobromide (HBr.)

[Voltech]

Hello,

somebody knows the potency differences between the 2CB Hidrochloride salt and the hidrobromide?

I heard HCL is more potent, but how much?

10mg of HCL = Xmg. HBr. ?

Thanks in advise!

 

[fastandbulbous]

It's just a bit of simple maths. Divide the RMM of 2C-B.HCl by the RMM of 2C-B.HBr and multiply by 10mg to get an equipotent dose of the hydrochloride salt

 

[nndmt]

...

 

[C6H6]

1.15g 2CB.HBr = 1.00g 2CB.HCl

 

[Voltech]

Thanks all!


-----------------------

a friend done the homework for me:

2c-b: C10H14BrNO2

(RMM(2c-b)+RMM(HCl)/RMM(2c-b)+RMM(HBr))*10mg

RMM(2c-b)=10*12,01+14+79,9+14+2*15,99=120.1+14+79.9+14+31.98=259.98
RMM(HCl)=1+35.45=36.45
RMM(HBR)=1+79.99=80.99

RMM(2c-b.HCl)=296.43
/RMM(2c-b.HBr)=340.97
=0.869
*10
=8.69

10 mg. 2c-b.HBr = 8.69 mg 2c-b.HCl.

---------------------------

 

[C6H6]

And if you divide 10 mg / 8.69 mg you'll get the same ratio I gave: 1.15.