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2,5-Dimethoxy-4-Hydroxyphenethylamine (2C-OH?)

I want to see a piperazine... i.e. close off the amine into the benzyl group to make the compound a bicyclo.
 
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I know this is an old thread, but it seems to me that you all missed a very simple synthesis tech which anyone could pull off and test the activity of this compound themselves.

Iodine is the most potent leaving group that I know of.

A substitution reaction should be possible by adding and heating a solution of NaOH to a sample of 2C-I how much however is up to you to decide, I personally do not and will not order RC's online and so have none and have only sampled 2C-E which I preferred to any acid trip.

The activity 2C-OH does intrigue me however so if any of you decide to try this post about your exp.
 
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Don't know much about the bbb but considering 2C-F is active (albeit in a pretty naff manner compared to it's counterparts) then surely polarity won't be the issue? Or do hydroxy groups effect bbb permeability differently to the halogens (perhaps due to F's crazy charge density?)
 
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