Ballz_Trippington
Bluelighter
- Joined
- Sep 18, 2013
- Messages
- 1,293
Yup just the one.
Yup just the one.
All this was addressed in this very thread if you bothered to read it...
Separating the isomers via chromatography is actually the last step in LSD synthesis... yiu should read a few posts above .
Edit: Unless the syntheses are done such that no (-)LSD is formed. In that case, obviously, one would not need to worry about separating the two. That was my original question: Are LSD synths stereoselective, as in they do not produce all possible enantiomers to begin with?
I see mention of iso-LSD, but no mention of (+)LSD or (-)LSD. I did read the whole thread, by the way.
http://upload.wikimedia.org/wikiped...ide_stereoisomers_structural_formulae_v.2.png
What is the process for separating (+)LSD and (-)LSD? There was brief mention of a chiral substrate, which I could see being able to separate the two.
Edit: Unless the syntheses are done such that no (-)LSD is formed. In that case, obviously, one would not need to worry about separating the two. That was my original question: Are LSD synths stereoselective, as in they do not produce all possible enantiomers to begin with?