serotonin2A
Bluelighter
- Joined
- Sep 13, 2014
- Messages
- 1,354
I'm not sure I understand your question correctly, but you know that unless there is a covalent bond formed (irreversible binding) the free drug and drug-receptor complex are in dynamic equilibrium, meaning that it attaches and detaches very quickly all the time. The affinity of the antagonist in comparison to the endogenous ligand determines at what concentrations of said drug you can talk about sufficient receptor blockade, so knowing that you can estimate how long it will take for the concentration to fall below a certain "threshold". The drug you're taking isn't an irreversible antagonist, right? Because in that case half-life would have little meaning.
I'm a little confused by your answer to his question. The free drug and drug-receptor complex are only at dynamic equilibrium when the concentration = the Kd. Ligands don't necessarily attach and detach very quickly -- it depends on the on-rate (Kon) and off-rate (Koff) of the particular ligand.
The affinity (Kd) = Koff/Kon. So a ligand can have high affinity if it has a slow disassociation rate, a fast association rate, or both. You can think about it like this: if the ligand and receptor associate faster than they can disassociate, then ligand-receptor complex will start to accumulate relative to the free receptor and the free ligand. Hence the Kd will occur at a lower concentration (ie, higher affinity).
But ultimately the length of time that a ligand stays bound to the receptor varies across ligands. Some ligands like buprenorphine and LSD have very long off-rates and are pseudoirreversible.