Very confused on this...hoping someone can explain.
I know that Ki values refer to binding affinities, and the lower the Ki, the higher the affinity a drug has for a receptor/transporter.
When looking at Focalin (the D enantiomer of methylphenidate, which I know is about twice as potent as racemic methylphenidate, I see that the Ki value for the DAT is listed as 161, whereas the L enantiomer is 2250..obv a much lower affinity.
However, the racemic mixture of methylphenidate (Ritalin) which contains half dextro and half levo methylphenidate, the Ki value for the DAT is 121....meaning the racemic mixture has an even higher affinity for DAT than the isolated dextro enantiomer.
How is it possible that when you combine dextro (high affinity), with levo (low affinity), the final product ends up being something with a higher affinity than the isolated high affinity enantiomer.
If anything u would expect the affinity of the racemic mixture to fall somewhere in between the affinity of the high affinity dextro enantiomer and low affinity levo enantiomer, and yet somehow the affinity turns out to be greater than that of its highest affinity enantiomer.
It's like mixing chocolate and vanilla ice cream and the result being a nice cream that is darker brown than chocolate itself.
What am I missing
I know that Ki values refer to binding affinities, and the lower the Ki, the higher the affinity a drug has for a receptor/transporter.
When looking at Focalin (the D enantiomer of methylphenidate, which I know is about twice as potent as racemic methylphenidate, I see that the Ki value for the DAT is listed as 161, whereas the L enantiomer is 2250..obv a much lower affinity.
However, the racemic mixture of methylphenidate (Ritalin) which contains half dextro and half levo methylphenidate, the Ki value for the DAT is 121....meaning the racemic mixture has an even higher affinity for DAT than the isolated dextro enantiomer.
How is it possible that when you combine dextro (high affinity), with levo (low affinity), the final product ends up being something with a higher affinity than the isolated high affinity enantiomer.
If anything u would expect the affinity of the racemic mixture to fall somewhere in between the affinity of the high affinity dextro enantiomer and low affinity levo enantiomer, and yet somehow the affinity turns out to be greater than that of its highest affinity enantiomer.
It's like mixing chocolate and vanilla ice cream and the result being a nice cream that is darker brown than chocolate itself.
What am I missing