N&SADD:Social Thread. whipping hair bak and forth

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A farmer buys 100 animals for $100. The animals include at least one cow, one pig, and one chicken. If a cow costs $10, a pig costs $3, and a chicken costs $0.50, how many of each did he buy?


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94 chickens, 1 pig, 5 cows.

The number of chickens must be greater than 80, because otherwise, you couldn't have a single cow in the remaining animals without going over $100. Also, the number of chickens must be odd, because otherwise, you can't get an even dollar amount ($100).

So, we let N denote the number of chickens, and we see that N = 94 (by exhaustion, for N = 82, 84, 86..98) is the only value for which the system of equations 10c + 3p = 100 - .5N and c + p = 100 - N has integer solutions for c and p.

Concerning the anti-semetics of your post, that's obvious. Even moreso than this farm animal puzzle. JC is clearly jewish (read the Bible). So, your post was anti-semetic because it assumed that JC would construct a puzzle with a biggoted answer.
 
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