Been thinking about something. 2-methyl-2-butanol (herein, 2M2B) is more potent than ethanol, has a longer duration, less negative side effects, etc. So, creating a 2M2B solution equipotent to a typical 40% ABV vodka could be very beneficial.
So, here's what I'm thinking calculations-wise:
1 L 40% ABV Vodka => 400 mL EtOH, which should be about 315.6 g EtOH.
Seeing how 2M2B is about 20x more potent by weight (wiki), this would take 15.78 g of 2M2B or 19.36 mL of the stuff. So, with 19.36 mL 2M2B, you have enough stock material to make about a liter of decent and longer-lasting vodka.