Synaps3
Bluelighter
- Joined
- Sep 14, 2011
- Messages
- 257
Can someone explain why there are two expoxides forming in this metabolization?
I am a noob and number VI doesn't make sense.
Does this mean any tertiary alcohol (such as 2m2b) would first be converted to an epoxide and then to a diol or are both of these epoxides the result of the chloro-vinyl?
BTW I know this is a very nasty drug, but I'm trying to figure out if any tertiary alcohol would form an epoxide at some stage.
http://oi66.tinypic.com/mkg9lf.jpg
I am a noob and number VI doesn't make sense.
Does this mean any tertiary alcohol (such as 2m2b) would first be converted to an epoxide and then to a diol or are both of these epoxides the result of the chloro-vinyl?
BTW I know this is a very nasty drug, but I'm trying to figure out if any tertiary alcohol would form an epoxide at some stage.
http://oi66.tinypic.com/mkg9lf.jpg